How full can we pack a unit square with golden rectangles of any size? Similarly, how full can we pack a unit golden rectangle with squares of any size? If we use the greedy algorithm, every golden rectangle or square used fills a factor of ϕ-1 of the area. Can we improve upon this?
1![]() s = ϕ = 1.618+ | 2![]() s = 2 | 3-4![]() s = 1 + ϕ = 2.618+ | 5-6![]() s = 2ϕ = 3.236+ | 7-8![]() s = 2 + ϕ = 3.618+ |
9-10![]() s = 1 + 2ϕ = 4.236+ | 11-12![]() s = 3 + ϕ = 4.618+ | 13![]() s = 3ϕ = 4.854+ | 14-15![]() s = 5 | 16![]() s = 2 + 2ϕ = 5.236+ |
17-18![]() s = 4 + ϕ = 5.618+ | 19-20![]() s = 1 + 3ϕ = 5.854+ | 21![]() s = 6 | 22-24![]() s = 3 + 2ϕ = 6.236+ | 25-26![]() s = 5 + ϕ = 6.618+ |
27-28![]() s = 2 + 3ϕ = 6.854+ | 29![]() s = 7 | 30-32![]() s = 4 + 2ϕ = 7.236+ | 33-35![]() s = 6 + ϕ = 7.618+ | 36-37![]() s = 3 + 3ϕ = 7.854+ (MM) |
38![]() s = 8 (MM) | 39-40![]() s = 5ϕ = 8.090+ |
1![]() s = 1 | 2![]() s = ϕ = 1.618+ | 3![]() s = 3/ϕ = 1.854+ | 4![]() s = 2 | 5-6![]() s = 1 + ϕ = 2.618+ |
7![]() s = 1 + 3/ϕ = 2.854+ | 8-9![]() s = 3 | 10![]() s = 2ϕ = 3.236+ | 11![]() s = 1 + 4/ϕ = 3.472+ | 12![]() s = 2 + ϕ = 3.618+ |
13![]() s = 6/ϕ = 3.708+ | 14-16![]() s = 4 | 17![]() s = 1 + 2ϕ = 4.236+ | 18![]() s = 7/ϕ = 4.326+ | 19-20![]() s = 3 + ϕ = 4.618+ |
21![]() s = 1 + 6/ϕ = 4.708+ | 22![]() s = 3ϕ = 4.854+ | 23-24![]() s = 8/ϕ = 4.944+ | 25![]() s = 5 | 26![]() s = 2 + 2ϕ = 5.236+ |
27![]() s = 1 + 7/ϕ = 5.326+ | 28![]() s = 3 + 4ϕ = 5.472+ | 29-31![]() s = 4 + ϕ = 5.618+ | 32-33![]() s = 1 + 3ϕ = 5.854+ | 34![]() s = 1 + 8/ϕ = 5.944+ |
35-36![]() s = 6 |
1![]() s = 1 | 2![]() s = 2/ϕ = 1.236+ | 3![]() s = 3/ϕ = 1.854+ | 4-6![]() s = 2 | 7![]() s = 2.450+ (MM) |
8![]() s = 4/ϕ = 2.472+ | 9![]() s = 2.830+ (MM) | 10![]() s = 2.945+ (MM) | 11-12![]() s = 3 | 13-15![]() s = 5/ϕ = 3.090+ |
16![]() s = 3.589+ (MM) | 17-18![]() s = 6/ϕ = 3.708+ | 19![]() s = 3.876+ (SB) | 20![]() s = 3.963+ (MM) | 21-24![]() s = 4 |
25![]() s = 4.294+ (MM) | 26-28![]() s = 7/ϕ = 4.326+ | 29![]() s = 4.676+ (MM) | 30![]() s = 4.741+ (MM) | 31![]() s = 4.834+ (MM) |
32![]() s = 4.921+(MM) | 33![]() s = 8/ϕ | 34![]() s = 4.969+ (MM) | 35-40![]() s = 5 |
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